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Let’s assume that’s the case; that would mean that s1 = s2 regardless of our choice of K2. However, in the irrational case, we’ve established that s1 is necessarily a positive number. We can make the 1 / K2 fraction arbitrarily small by increasing K2, so no matter how small s1 is, the right-hand fraction can be made smaller to flip the inequality. This produces a contradiction. It must be that for a given irrational r and some chosen K2 K1, the equation will produce a new, distinct a2 / b2 such that s2
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工具一览计划与执行：Obsidian + Claude CodeObsidian 是我的主要任务管理工具，让 Claude Code 读取 100 Days of SwiftUI 课程总览页面，就可以直接根据课程内容在 Obsidian 中生成一则 Tasks-100 Days of SwiftUI 待办清单，当中用：
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